koi solve kr do.......
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Consider V to be the voltage acRoss the capacitor when the dielectric is not placed
The voltage decreases in the area where the dielectric is placed
V1=V/K1=V/2K2
V2=V/K2
Now substitute V/K2 as V2 in V1
V1=V2/2
V2=2V1
I hope this helps ( ╹▽╹ )
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