Question

koi to bta do answer.....

no spamming

Answer 1

I hope this will help you.

Answer 2

Let the tens digit be x.

Given that unit's digit exceeds its tens digit by 2.

Then the units digits = x + 2.

Hence, the original number = 10x + (x + 2)

= > 10x + x + 2

= > 11x + 2    ----- (1)

(i)

Given that product of its digit and sum of its digit is equal to 144.

= > (11x + 2)(x + x + 2) = 144

= > (11x + 2)(2x + 2) = 144

= > 22x^2 + 22x + 4x + 4 = 144

= > 22x^2 + 26x + 4 = 144

= > 22x^2 + 26x = 140

= > 22x^2 + 26x - 140 = 0

= > 11x^2 + 13x - 70 = 0

= > 11x^2 - 22x + 35x - 70 = 0

= > 11x(x - 2) + 35(x - 2) = 0

= > (x - 2)(11x + 35) = 0

= > x = 2, x = -35/11{x cannot be negative].

= > x = 2.

Now,

Substitute in (1), we get

= > 11x + 2

= > 11(2) + 2

= > 24

Therefore, the number is 24.

Hope this helps!