Question

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Answer 1

Answer:

(6/5 -7/9)

54-35/45

19/45 +X =1/2

X =1/2-19/45

=45-38/90

=7/90

Step-by-step explanation:

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Answer 2

Question 1:

• What should be added to $\sf \: ( \frac{6}{5} - \frac{7}{9} )$ to get $\sf \: \frac{1}{2}$?

SolutioN:-

Let the number be 'x'.

So, According to question

$\implies \sf \: x + ( \frac{6}{5} - \frac{7}{9} ) = \frac{1}{2}$

$\implies \sf \: x = ( \frac{54 - 35}{45} ) = \frac{1}{2}$

$\implies\sf \: x + \frac{19}{45} = \frac{1}{2}$

$\implies \sf \: x = \frac{1}{2} - \frac{19}{45}$

$\implies \sf \: x = \frac{45 - 38}{90}$ $\implies\sf \: x = \frac{7}{90}$

Verification:-

$\implies \sf \: x + ( \frac{6}{5} - \frac{7}{9} ) = \frac{1}{2}$

• Put x = 7/90

$\implies \sf \: \frac{6}{90} + ( \frac{54-35}{45}) = \frac{1}{2}$

$\implies \sf \: \frac{6}{90} + \frac{19}{45} = \frac{1}{2}$

$\implies \sf \: \frac{7+38}{90} = \frac{1}{2}$

$\implies \sf \: \frac{45}{90} = \frac{1}{2}$

$\implies \sf \: \frac{1}{2} = \frac{1}{2}$

Therefore,

Number is 7/90.

So, 7/90 should be added to $\sf \: ( \frac{6}{5} - \frac{7}{9} )$ to get $\sf \: \frac{1}{2}$.

__________________________________

Question 2:

• Find area of rectangle whose length is $\sf \: 4 \frac{4}{5} cm$ and Breadth is $\sf \: 1 \frac{4}{6} cm$.

SolutioN:-

Given that,

Length of rectangle = $\sf \: 4 \frac{4}{5} cm$ = $\sf \frac{24}{5} cm$

Breadth of rectangle = $\sf \: 1 \frac{4}{6} cm$ = $\sf \frac{10}{6} cm$

We know that,

Area of rectangle = length × Breadth

So,

$\implies \sf \frac{24}{5} \times \frac{10}{6}$

$\implies \sf \frac{240}{30}$

$\implies \sf 8$

Therefore,

Area of rectangle is 8 cm².