Question

Koi to solve kr do isko please xD​

Answer 1

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Answer 2

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1. The radius of the nucleus  is: R = 1.25 × 10⁻¹³

Now, we have assumed here that The nucleus is a sphere, so, the volume of the sphere is: $\frac{4}{3}$πr³

Now, radius of the atom formula = radius of nucleus x cube root of mass number of the atom

= 1.25 × 10⁻¹³ x  = 1.25 x 10⁻¹³ x 4 = 5 x 10⁻¹³

now, radius of atom = 1 Å = 10⁻¹⁰ m = 10⁻⁸ cm (multiply by 100, since all the values are given in cm)

Volume occupied by the nucleus in the atom is:

$\frac{Volume_n_u_c_l_e_u_s}{Volume_a_t_o_m}$ = $\frac{(5x10^-^1^3)^3}{(10^-^8)^3}$ ($\frac{4}{3}$π get cancelled both in the numerator and denominator)

= $\frac{125x10^-^3^9}{10^-^2^4}$ = 125 x 10⁻¹⁵ cm = 1.25 x 10⁻¹³ cm

2. The value of n will be only natural numbers (not even 0)

Now, the formula of the excited state of the hydrogen atom is: $\frac{-13.6eV}{n^2}$

If n=1, then, $\frac{-13.6eV}{1^2}$ = -13.6eV

if n=2, then, $\frac{-13.6eV}{2^2} = \frac{-13.6eV}{4}$ = -3.4eV

so, the possible value is only option (a) -3.4 eV