Question

koi zinda hai


Q1.A car travels a distance 100 m with a constant
acceleration and average velocity of 20 m s-1. The final velocity acquired by the car is 25m/s .Find :(1) the initial velocity and (2) acceleration of the car .​​​

Answer 1

Step-by-step explanation:

Average velocity=

2

v+u

20=

2

25+u

u=15 m/s

v=u+at

25=15+a×5

We get, a=2 m/s

2

Answer 2

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Distance travelled s = 100 m

Average velocity V = 20 m/s

Final velocity v = 25 m/s

(i) Let u be the initial velocity.

Average velocity = (Initial velocity + Final velocity)/2

V = (u + v)/2

20 = (u + 25)/2

u = 40 - 25 = 15 m/s-1

(ii) Let 'a' be the acceleration of the car.

Using the third equation of motion,

v2 - u2 = 2as

We get,

(25) 2 - (15) 2 = 2 (a) (100)

625 - 225 = 200 a

a = (400/200) m/s2 = 2 m/s-2