Question

Koihai

Q1. point charges 4Q, Q are separated by lm in air. At what point on the line joining the charges is the electric field intensity zero?Also calculate the electrostatic potential energy of the system of charges, taking the value of charge, Q = 2 ×10^-7C.

Answer 1

Answer:

4kq/x²=kq/(1-x)²=>{×/(1-x)}²=4=>x/(1-x)=2

=>x=2–2x=>3x=2=>x=2/3.Ans.

Step-by-step explanation:

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