Question

Konechiva guys
Please solve the Question2 in the attachment​

Answer 1

Answer:

Ello..❤

n(n+1)=n2+1

=((n+1)−1)(n+1)

=(n+1)2−(n+1)

So if (n+1) is an even no (n+1)2 is even and diff of even is always even is (n+1).

If odd then (n+1)2 is odd and diff of odd is always even 

So n(n+1) is always even and divisible by 2

Hope it helps...❤❤