KONJAM HELP PANNUNGA
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Step-by-step explanation:
√(1-cosA /1+cosA) + √(1+cosA/1-cosA)
= √ (2sin^A/2 /2cos^A/2) + √(2cos^2A/2 / 2sin^2A/2)
(formula used
1-cosA = 2sin^2A/2
1+ cosA = 2cos^2A/2
sinA/2 / cosA/2 = tanA/2)
= tanA/2 + cotA/2
= tanA/2 + 1/tanA/2
= tan^2A/2 + 1 / tanA/2
= sec^2 A/2 / tanA/2
= (1/cos^2A/2) / sinA/2/cosA/2
= tanA/2 (answer)
hope u understood it my friend.
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