Question

Koogle
Test Level-3 (Unit-6)

A force of 0.01 N is exerted on a charge of 1.2 x 10-5 C. at a certain point. The electric field at that point is
A) 5.3 x 106 N/C
B) 8.3 x 106 N/C
C) 5.3 x 106 N/C
D) 8.3 x 102 N/C

Answer 1

Here applying

Formula:

$e = \frac{f}{q}$

where e is electric field and f is force.

f here is = 0.01N

q =

$1.2 \times {10}^{ - 5}$

so,

$\frac{0.01}{1.2 \times {10}^{ - 5} } \\ solving \: this \: we \: get \\ e = 8.3 \times {10}^{2} n {c}^{ - 1}$

Hope this gonna help you ♡(∩o∩)♡