Question

Kp= 32 Find Kc at 300K temperature?​

Answer 1

Answer:

Kp=Kc(RT)

Δn

since Δn=1, then Kc(RT)

9=Kc×0.0821×300

Kc=0.3654

Kc=

[C]

[A][B]

=

1

X

2

=0.3654

x=0.6044

average molecular weight =70×0.455+49×0.27+21×0.27=50