Question

Kp for the reaction A ⇌ B is 4. If initially only A is present then what will be the partial pressure of B after equilibrium?

Answer 1

here A⇄B

INITIALLY  1atm of A and 0 of B

At equilibrium 1-Px of A and Px of B

Kp= 4  

then 4= Px / 1-Px

Px= 4/5 atm

plzzz mark as brainliest