Physics, asked by anvigupta72, 2 months ago

kriday moves in a circular track of radius of 12 m .if he complete two and half revolution along the circular track,then find the distance and displacement covered by him​

Answers

Answered by NewGeneEinstein
2

Explanation:

Figure:-

\setlength{\unitlength}{1mm}\begin{picture}(50,55)\linethickness{0.4mm}\qbezier(45,30)(45,30)(5,30)\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\multiput(5,30)(20,0){3}{\circle*{1}}\end{picture}

  • Firstly we have to find circumference .
  • Because the particle moving around a circular track .

Radius=r=12m

\boxed{\sf Circumference=2πr}

\\ \tt {:}\Rrightarrow 2\times \dfrac{22}{7}\times 12

\\ \tt {:}\Rrightarrow \dfrac{44\times 12}{7}

\\ \tt {:}\Rrightarrow \dfrac{528}{7}

\\ \tt {:}\Rrightarrow 75.4

\\ \tt {:}\Rrightarrow 75m (Approx)

Now ,

Distance traveled=2.5×Circumference

\\ \tt {:}\Rrightarrow 2.5\times 75

\\ \tt {:}\Rrightarrow 187.5m

And,

Displacement=2×Radius

\\ \tt {:}\Rrightarrow 2×12

\\ \tt {:}\Rrightarrow 24m

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