Math, asked by satishbiradar, 1 year ago

Krish 1 - tan square by 1 minus cot a square is equal to tan square,A angle A is acute

Answers

Answered by kvnmurty

To prove that
$\frac{1-tan^2A}{1-Cot^2A} = - tan^2 A\\\\LHS: \frac{1-\frac{sin^2A}{cos^2A}}{1-\frac{Cos^2A}{Sin^2A}}=\frac{cos^2A-sin^2A}{sin^2A-cos^2A}*\frac{sin^2A}{cos^2A}\\\\=- tan^2A$

Hope it is clear.

kvnmurty: :-)

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