Krish has a mass of 60 kg. While running at a speed of 4.5 m/s, he jumps on to a 20 kg trolley
travelling in the same direction at 2.5 m/s. Find the common velocity of Krish and the trolley.
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The effort arm (or arm of applied force) is the portion of the lever to which we apply the effort, or input force. ... In a first-class lever, the effort arm and load arm are located on opposite sides of the fulcrum, and effort is applied in the same direction as the force exerted by the load.
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On the principle of conservation of momentum
mv + MV = (m + M)V1
Where
m = mass of the boy = 60 kg
v = velocity of the boy = 3 m/s
M = mass of the trolley = 140 kg
V = velocity of the trolley = 1•5 m/s
V1 = velocity of the combined system in m/s = ?
60*3 + 140*1•5 = (60 + 140)V1
V1 = (180 + 220)/200 = 400/200 = 2 m/s
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