Question

Krishna purchased an old scooter for 8000 if it's cost after 2 years is 6480 what is the rate of depriciation

Answer 1

Step-by-step explanation:

Let the rate of depreciation be r%.

According to question,

6480=8000((1-(r/100))^2)

or, 6480/8000=(1-(r/100))^2

or, 81/100=(1-(r/100))^2

or, (9/10)^2=(1-(r/100))^2

or, 9/10=1-(r/100)

or, 9/10=(100-r)/100

or, (9/10)*100=100-r

or, 90=100-r

or, r=10

Therefore, rate of depreciation in 10%.

Answer 2

Answer:

Hey mate!!! This is your answer.......