Question

Krishna purchased an old scooter for Rs.8000.ignoring its cost after 2 years is Rs6480, what is the rate of depreciation?

Answer 1

Hello...

Here's your answer...

Let rate of depreciation = r %

We know formula for compound interest :

Amount = Here P (1+r/100)^t = 8000

t  =  2 ,

Compound interest = 6480

8000 + (1+r/100)^2 = 6480
(1+r/100)^2 = 6400/8000
(1+r/100)^2 = 81/100
(1+r/100)^2 = 9^2/10^2
1+r/100 = 9/10
r/100 = 9/10 - 1
r/100 = 9-10/10
r/100 = -1/10
r/100 -1/10×100
r = -10

negative sign shows that is a rate of depreciation


Rate of depreciation = 10 %              

Answer 2

Hey!!
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Given : Compound interest on a sum of Rs 8000 at a certain rate of interest compounded annually for 2 years is Rs 6480

Let rate of depreciation = r %

We know formula for compound interest :

Amount = P(1 +r100)t   , Here P  = 8000 , t  =  2 , Compound interest = 6480 ,
So

8000 (1 + r100)2 = 6480

⇒(1 + r100)2 = 64808000 
⇒(1 + r100)2 = 81100 
⇒(1 + r100)2 = 92102 
⇒(1 + r100)2 = (910 )2
⇒1 + r100= 910 
⇒r100= 910  − 1
⇒r100= 9 − 1010 
⇒r100= − 110 
⇒r= − 110 ×100
⇒r= − 10

Here negative sign shows that is a rate of depreciation .

Therefore,
Rate of depreciation = 10% Ans


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