Question

Krishna sells two tables for Rs. 6,000/- each. He gains 20% on first to
and on the second he loses 20%.
1) Find the cost price of the first table?
ii) Find the cost price of the second table?
iii) What is the total cost price of the two tables?
iv) Find his gain or loss percent on whole transaction?​

Answer 1

(1) Rs. 5000

(2) Rs 7500

(3) Rs. 12500

(4) 4%.

Step-by-step explanation:  Let x represents the cost price of the first table and y represents the cost price of the second table.

(1) Since Krishna sells first table at a profit of 20%, so we have

$x+20\%\times x=6000\\\\\\\Rightarrow x+\dfrac{20}{100}\times x=6000\\\\\\\Rightarrow x+\dfrac{x}{5}=6000\\\\\\\Rightarrow \dfrac{6x}{5}=6000\\\\\Rightarrow x=\dfrac{6000\times5}{6}\\\\\Rightarrow x=5000.$

So, the cost price of the first table is Rs. 5000.

(2) Since Krishna sells second table at a loss of 20%, so we have

$y-20\%\times y=6000\\\\\\\Rightarrow y-\dfrac{y}{5}=6000\\\\\\\Rightarrow \dfrac{4y}{5}=6000\\\\\\\Rightarrow y=\dfrac{6000\times5}{4}\\\\\Rightarrow y=7500.$

So, the cost price of the second table is Rs. 7500.

(3) The total cost price of the two tables is

$x+y=Rs.(5000+7500)=Rs. 12500.$

(4) The total C.P. = RS. 12500  and the total S.P. = Rs. (6000 + 6000) = Rs 12000.

So, loss = Rs. (12500 - 12000) = Rs. 500.

Therefore, the loss percent is given by  

$\dfrac{500}{12500}\times100\%=\dfrac{500}{125}\%=4\%.$

So, the required loss percent is 4%.