Math, asked by agarwalpurvi3754, 1 year ago

Krishna sells two tables for Rs. 6,000/- each. He gains 20% on first toand on the second he loses 20%.1) Find the cost price of the first table?ii) Find the cost price of the second table?iii) What is the total cost price of the two tables?iv) Find his gain or loss percent on whole transaction?​

Answers

Answered by subhashnidevi4878
0

Cost price of first table is 5000 Rs

Cost price of second table is 7500 Rs

Step-by-step explanation:

Krishna sells two tables each 6000 rs.

Selling price of two tables = 6000 + 6000

= 12000 rs.

1. If he gain 20% profit on first table,

then,

120% = 6000

100% = \frac{6000}{120}\times 100

100% = 5000 rs.

So, cost price of first table is 5000 Rs

2. if he loss 20% on second table,

So, 80% = 6000

100% = \frac{6000}{80}\times 100

100% = 7500 rs

cost price of second table is 7500 Rs

3. Total cost price of two tables = 5000 + 7500

                                                     = 12500 rs

4. loss or profit on whole transaction,

SP = 12000

CP = 12500

Profit or loss = 12500 - 12000

= 500 (loss)

loss percentage = \frac{500}{12500}\times 100

= 4 %

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