Ksp of Mg(OH), is 9 x 10-12 if the concentration of Mg+ ion is 0.01 M, then
find the concentration of OH-ion-
(1) 9 x 10-10
(2) 3 x 10-5
(3) 9 x 10-12
(4) 3 x 10-7
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Mg(OH)
2
⇌Mg
2+
+2[OH]
−
⇒K
sp
=[Mg
2+
][OH
−
]2
Given, K
sp
=9×10
−12
[Mg
2+
]=0.01M
[OH
−
]=
[Mg
2+
]
K
sp
=
10
−2
9×10
−12
∴[OH
−
]=3×10 −5
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