Question

Kts
For what value of n, are the nth terms
of twoAps, 13,19,25.... and
69,68,67... .: equal?

Answer 1

Answer:

For n=9 the nth terms of the two APs will be equal.

Step-by-step explanation:

AP1= 13,19,25,....

a=13

d=6

Tn¹= a+(n-1)d

= 13+(n-1)6

= 13+6n-6

= 7+6n

AP2= 69,68,67,....

a=69

d=-1

Tn²= a+(n-1)d

= 69+(n-1)-1

= 69-n+1

= 70+n

Now,

Tn¹ = Tn²

7+6n = 70-n

6n+n = 70-7

7n = 63

n = 9

Hope it helps!