Question

⬆️☜ (↼_↼).......Kuch Smjh ni aaya......







A scooter moving a speed of 10m /sec. his stoped by appling
breaks which produce a universal according form-0. 5 m/ sec. how much distance will be the scooter will be cover before 8 stops

cLass-9th, CBSE board, NCERT...

Don't Spam.....
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Answer 1

Answer:

Here, Initial speed, u = 10 m/s

Final speed, v = 0 (Scooter stops)

Acceleration, a = -0.05 m/s2

And, Distance covered, s = ? (To be calculated)

Now, putting these values in the third equation of motion :

v2=u2+2as

We get : (0)2=(10)2+2×(−0.5)×s

0=100−s

s=100 m

Thus, the distance covered is 100 metres.