Question

Kunal is 6 times as old his son 2 years ago Kunal was 8 times as old as his son find his son's age

Answer 1

$<b><i>Solutions:-$


Let the son's age be x
Father's age = 6x


2 years ago :-

Son's age = x - 2
Father's age = 6x - 2


Now,

A/q

6x - 2 = 8( x - 2)

=> 6x - 2 = 8x - 16

=> - 2+16 = 8x - 6x

=> 14 = 2x

=> x = 14/2 = 7



Hence,

The son's age = x = 7 years






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Answer 2

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$<b><i>ANSWER:-$
accordingly let son's age = x
then kunal's age =6x

now second condition is for 2 years ago.
so two year ago:-

son's age =x-2
and kunal'sage=6x-2

but here is a condition that two years ago kunal was 8 times old so here to balance:-

8×(son's age )=kunal's age
or 8×(x-2)=6x-2
or 8x-16=6x-2
or 2x = 14
or x=7

This is what you asked kunals son's age is $\boxed{7\: years }$

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