Kunal is 6 times as old his son 2 years ago Kunal was 8 times as old as his son find his son's age
Answers
Answered by
31
Let the son's age be x
Father's age = 6x
2 years ago :-
Son's age = x - 2
Father's age = 6x - 2
Now,
A/q
6x - 2 = 8( x - 2)
=> 6x - 2 = 8x - 16
=> - 2+16 = 8x - 6x
=> 14 = 2x
=> x = 14/2 = 7
Hence,
The son's age = x = 7 years
Anonymous:
Great answer !!
Answered by
57
☺️HEY DEAR!!☺️

accordingly let son's age = x
then kunal's age =6x
now second condition is for 2 years ago.
so two year ago:-
son's age =x-2
and kunal'sage=6x-2
but here is a condition that two years ago kunal was 8 times old so here to balance:-
8×(son's age )=kunal's age
or 8×(x-2)=6x-2
or 8x-16=6x-2
or 2x = 14
or x=7
This is what you asked kunals son's age is
accordingly let son's age = x
then kunal's age =6x
now second condition is for 2 years ago.
so two year ago:-
son's age =x-2
and kunal'sage=6x-2
but here is a condition that two years ago kunal was 8 times old so here to balance:-
8×(son's age )=kunal's age
or 8×(x-2)=6x-2
or 8x-16=6x-2
or 2x = 14
or x=7
This is what you asked kunals son's age is
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