Question

Kunal’s age is seven times the age of his son. Ten years later, his age will be thrice the age of his son then. Taking Kunal's age to be x years and the son's age to be y years, find their present ages.

Answer 1

Given :

• Kunal's age is 7 times the age of his son.
• 10 years later , his age will be thrice the age of his son then.

To find :

• Their present ages.

Solution :

Consider,

• Present age of Kunal = x years
• Present age of his son = y years

${\underline{\sf{According\:to\: the\:1st\: condition:-}}}$

• Kunal's age is 7 times the age of his son.

$\to\sf{x=7y...................(1)}$

${\underline{\sf{According\:to\: the\:2nd\: condition:-}}}$

• 10 years later , his age will be thrice the age of his son then.

10 years later,

• Age of Kunal = (x+10) years
• Age of his son = (y+10) years

$\to\sf{x+10=3(y+10)}$

$\to\sf{x+10=3y+30}$

• Put x = 7y from eq(1).

$\to\sf{7y+10=3y+30}$

$\to\sf{7y-3y=30-10}$

$\to\sf{4y=20}$

$\to\sf{y=5}$

• Present age of son = 5 years
• Present age of Kunal = 7×5 = 35 years.

Answer 2

$\bf\huge\underline{ANSWER}$

Let ,

→ Present age of Kunal = x years

→ Present age of his son = y years

After 10 years ,

→ Age of Kunal = x + 10 years

→ Age of his son = y + 10 years

______________________________________

According to the first condition ,

$\Longrightarrow\rm x=7y \ \ \ \ \ \ \ \ .............(1)$

______________________________________________

According to the second condition ,

$\rm\longrightarrow x+10=3(y+10)\\\\\longrightarrow x+10=3y+30$

Put the value of x in Eq(1)

$\rm \longrightarrow 7y+10=3y+30\\\\\longrightarrow 7y-3y=30-10\\\\\longrightarrow 4y=20\\\\\longrightarrow y=5$

______________________________________________

Present age of Kunal = 35 years

Present age of his son = 5 years

______________________________________________

HOPE IT HELPS U ............