Kushal's age is three times the sum of the ages of his two sons and 5 years hence, his age will be double the sum of their ages. find kushal's present age.
Answers
Let the sum of ages of two sons be x years
Age of man = 3x years
After 5 years age of the man = (3x + 5) years
Sum of ages of two sons = (x + 10) years
Given, (3x + 5) = 2(x + 10)
⇒ (3x + 5) = 2x + 20
⇒ x = 15
Hence 3x = 3(15) = 45
So Kushal's age is 45 years.
Present age of man is 45 years.
Given :-
The age of a man is three times the sum of the ages of his two sons.
5 years hence, his age will be double the sum of their ages.
To find :-
Present age of man.
Solution :-
Let ,
Man's present age = x years
Present age of 1st son = y years
Present age of 2nd son = z years
The age of a man is three times the sum of the ages of his two sons.
➪ x = 3(y+z)
➪ y+z = x/3 ..................(i)
5 years hence, his age will be double the sum of their ages
5 years hence,
Man's age = (x+5) years
Age of 1st son = (y+5) years
Age of 2nd son = (z+5) years
➪ x+5 = 2[(y+5)+(z+5)]
➪ x+5 = 2(y+z+10)
[ put y+z = x/3 from eq (i)]
➪ x+5 = 2(x/3 + 10)
➪ x+5 = 2x/3 + 20
➪ x - 2x/3 = 20-5
➪ x/3 = 15
➪ x = 45
† Present age of man is 45 years.