Math, asked by SumitiChaudhary8444, 1 year ago

Kushal's age is three times the sum of the ages of his two sons and 5 years hence, his age will be double the sum of their ages. find kushal's present age.

Answers

Answered by Shaizakincsem
16

Let the sum of ages of two sons be x years

Age of man = 3x years

After 5 years age of the man = (3x + 5) years

Sum of ages of two sons = (x + 10) years

Given, (3x + 5) = 2(x + 10)

⇒ (3x + 5) = 2x + 20

⇒ x = 15

Hence 3x = 3(15) = 45

So Kushal's age is 45 years.

Answered by Sambhavs
17

\huge\sf\underline{\pink{An}\purple{sW}\green{eR}}

Present age of man is 45 years.

Given :-

The age of a man is three times the sum of the ages of his two sons.

5 years hence, his age will be double the sum of their ages.

To find :-

Present age of man.

Solution :-

Let ,

Man's present age = x years

Present age of 1st son = y years

Present age of 2nd son = z years

\red{\underline{\sf{According\:to\:the\:1st\: condition:-}}}

The age of a man is three times the sum of the ages of his two sons.

➪ x = 3(y+z)

➪ y+z = x/3 ..................(i)

\red{\underline{\sf{According\:to\:the\:2nd\: condition:-}}}

5 years hence, his age will be double the sum of their ages

5 years hence,

Man's age = (x+5) years

Age of 1st son = (y+5) years

Age of 2nd son = (z+5) years

➪ x+5 = 2[(y+5)+(z+5)]

➪ x+5 = 2(y+z+10)

[ put y+z = x/3 from eq (i)]

➪ x+5 = 2(x/3 + 10)

➪ x+5 = 2x/3 + 20

➪ x - 2x/3 = 20-5

➪ x/3 = 15

➪ x = 45

† Present age of man is 45 years.

________________

Similar questions