Math, asked by akshitachauhan2015, 1 year ago

Kusum buys some chocolates at the rate of Rs. 10 per chocolate. She also buys an equal number of candies at the rate of Rs. 5 per candy. She makes a 20% profit on chocolates and 8% profit on candies. At the end of the day, all chocolates and candies are sold out and her profit is Rs. 240. Find the number of chocolates purchased. [detail answer]

Answers

Answered by shabana123
55
hope it's correct.........
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akshitachauhan2015: thanks
Answered by pinquancaro
120

Answer:

Number of chocolate purchased is 100.

Step-by-step explanation:

Given : Kusum buys some chocolates at the rate of Rs. 10 per chocolate. She also buys an equal number of candies at the rate of Rs. 5 per candy. She makes a 20% profit on chocolates and 8% profit on candies. At the end of the day, all chocolates and candies are sold out and her profit is Rs. 240.

To find : The number of chocolates purchased?

Solution :

Let the number of chocolate be 'x'.

Cost of 1 chocolate be Rs.10

The cost of x chocolates be Rs.10x.

Number of candies = Number of chocolates = x

The cost of 1 candies = Rs.5

The cost of x candies = Rs.5x

She makes a 20% profit on chocolates.

i.e. Profit on selling chocolate is  20% of 10x

\frac{20}{100}\times 10x=2x

She makes 8% profit on candies.

i.e.  Profit on selling candies is 8% of 5x

\frac{8}{100}\times 5x=\frac{2}{5}x

Total profit is Rs.240.

2x+\frac{2}{5}x=240

\frac{10x+2x}{5}=240

12x=1200

x=\frac{1200}{12}

x=100

Therefore, Number of chocolate purchased is 100.

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