Question

Kw for h2o is 9.62 ×10^-14 at 60 degree celsius what is the ph of pure water

Answer 1

It will be around 7. 13.3 is very alkaline, on par with a strong alkaline such as NaOH.

First, you need your Kw value. Just looked in my notes, and for 60 degrees it is 5.60 x 10-14 mol2 dm-6. Check the question and use the value from there. I'll use the 60 degrees value for this example.

Kw = [H+][OH-]

so [H+][OH-]

[H+](squared) = 5.60 x 10-14

[H+] = square root of 5.60 x 10-14

[H+] = 2.366 x 10-7 mol dm-3

-----
pH = -log10 [H+]

so log 2.366 x 10-7 = 6.62

pH = 6.62


Thats for 60 degrees

Answer 2

Answer:

Ph = 6.51

Explanation:

Refer the image attached