Kw for h2o is 9.62*10^14 at 60°c . What is the ph of waterat 60°c
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The answer shouldn't just be -log(9.5E-14).
Since Kw = Kb * Ka. In a neutal solution Kb = Ka. So we would take the sqrt(9.5E-14), obtaining 3.08E-7.
Now we take the -log(3.08E-7) = 6.51.
So 6.51 is the pH.
Since Kw = Kb * Ka. In a neutal solution Kb = Ka. So we would take the sqrt(9.5E-14), obtaining 3.08E-7.
Now we take the -log(3.08E-7) = 6.51.
So 6.51 is the pH.
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