Question

Kw for water is 6.4 × 10–13. The pH of water at t°C will be

Answer 1

TOPIC :- IONIC EQUILIBRIUM

CONCEPT :- Kw is called ionic product of water. Kw = [H+] [OH-]. And, pH = -log[H+]

SOLUTIONS

Given,

Kw = 6.4 × 10^-13

[H+]² = 6.4 × 10^-13

[H+] = 8 × 10-7

Thus,

pH = - log[8 × 10^-7]

=> pH = 7 - log8

=> pH = 7 - 2log2

=>pH = 7 - 0.6

=> pH = 6.4 Ans.