Math, asked by Aura6435, 9 months ago

Kx^2-2(k-1) x 1 has no roots in (-1, 1)

Answers

Answered by mohitlokhande91
0

Answer:

k = 2

Step-by-step explanation:

kx^2-2(k-1) × 1=0

k-2k+2=0

-k+2=0

-k=-2

k=2

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