Question

kx^2-6x+2+k=0
Please help with this problem

Answer 1

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Answer 2

Answer:

Ans is -9/2

Step-by-step explanation:

Kx^2-6x+2=0 is in the form the form of quadratic equation. To have equal roots we know the formula i.e b^2-4ac

a=k

b=(-6)

c=[-2]

b^2-4ac

(-6)^2-4k(-2)=0

36+8k=0

8k=-36

k=36/8

k=-9/2

I hope you have got ans