Question

kx^2+(k - 1)x - 1= 0 then k = ??​

Answer 1

Answer: answer is 1/x

Step-by-step explanation:

Kx^2+(k-1)x-1

Kx^2+kx-1x-1

Kx(x-1)-1(x-1)

(Kx-1)(x+1)

Kx-1=0

K=1/x. And x-1=0.x=1

Answer 2

Answer:

k=1/x is not necessary

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