Kx^2+(k+2)x-3=0 has roots which are real and positive
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(k+2)²-4k(-3)=0
k²+4k+4+12k=0
k²+16k+4+64=64
k²+16k+64=64-4=60
(k+8)²=60
k+8=√(60)
k= -8+√(-60)
Hope that helps you!!
k²+4k+4+12k=0
k²+16k+4+64=64
k²+16k+64=64-4=60
(k+8)²=60
k+8=√(60)
k= -8+√(-60)
Hope that helps you!!
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