Math, asked by chinmaychavan323280, 1 year ago

kx^2-x-1=0. then k=? x =1​

Answers

Answered by kamleshrudhra
1

kx² - x - 1 = 0

If x = 1

kx² - x - 1 = 0

k (1)² - 1 -1 = 0

k - 2 = 0

k = 2

Answered by Anonymous
2

k {x}^{2}  - x - 1 = 0 \\ k( {1})^{2}  - 1 - 1 = 0 \\ k - 2 = 0 \\ k = 2

Hope it helps you....

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