kx + 2y - 4 = 0;3y + 6 = 0 infinite solution
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Answered by
5
Answer:
For the system to have infinitely many solutions, lines must coincide each other
⇒ratio of respective coefficients must be equal (x, y and constant coefficients)
⇒k/4 = 2/3 = 6/9
⇒k= 8/3
Answered by
0
Answer:
kx+2y-4=0
0x+3y+6=0
for infinite solutions,
a1/a2=b1/b2=c1/c2
2/3=-4/6=k/0
k/0 is not a real number. So the value of k is not defined for infinite solution
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