Question

Kx square + 2 Y + 3 K is equal to the twice the product find the value of k​

Answer 1

Answer:

p(y) = ky2 + 2y - 3k

Compare p(y) with standard form ax2 + bx + c

a = k, b = 2, c = -3k

According to question,

Sum of zeroes = 2(Product of zeroes)

⇒−ba=2×ca

⇒−2k=2×−3kk

⇒2k=6

⇒k=13

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Answer 2

here's your answer

hope it helps