Question

kx(x-2√5)+10=0 ,find k? ​

Answer 1

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《SIMPLIFY THIS♣

⟼ kx(x-2√5)+10=0

⟼(x-2√5)+10=0/kx

⟼x-2√5+10=0

⟼ x=2√5-10

《PUT THE VALUE OF X♣

⟼x-2√5

⟼2√5-10-2√5

⟼-10

《NOW,♣

⟼ kx(x-2√5)+10=0

⟼kx(-10)+10=0

⟼-10k(2√5-10)+10=0

⟼k= -10/(-20√5+100)

《ANSWER♣

-10/(-20√5+100)