Question

kx(x-2)+6 =0 find value of k

Answer 1

HEY!!

Given kx(x – 2) + 6 = 0
kx2 – 2kx + 6 = 0
Since the given quadratic equation has equal roots  we have b2 – 4ac = 0
That is (– 2k)2 – 4(k)(6) = 0
⇒ 4k2 – 24k = 0
⇒ 4k(k – 6) = 0
⇒ 4k = 0 or (k – 6) = 0
∴ k = 0 or 6

Answer 2

Here we have :-

kx (x - 2) + 6 = 0

kx^2 - 2kx + 6 = 0

D = (-2k)^2 - 4(k)6

= 4k^2 - 24k

★For equal roots

4k^2 - 24k = 0

4k(k - 6) = 0

k = 0

k = 6

k ≠ 0

Hence k = 6