Question

Kx(x-2)+6=0
Find value of k by quadratic equation are real and equal

Answer 1

Explanation:

We have been given the quadratic equation , kx(x-2) + 6 = 0. We have to find the value of k.

• kx² - 2kx + 6 = 0

Here,We have to find the discriminant of the equation.

• D = b² - 4ac

Solve the Equation:

D = b² - 4ac

• For real and equal , The discriminant of quadratic equation is 0.

D = ( -2k)² - 4*k*6

0 = 4k² - 24k

4k² = 24k

4k= 24

k = 24/4

k = 8

• Therefore, The required Value of k is 8.