Question

Kx(x-3)+9=0 has two equal roots.

Answer 1

it may help you. .....

Answer 2

The value of k is 4.

Step-by-step explanation:

Given : Equation $Kx(x-3)+9=0$ has two equal roots.

To find : The value of k ?

Solution :

The equation is $Kx^2-3kx+9=0$

On comparing with quadratic equation $ax^2+bx+c=0$

Here, a=k, b=-3k and c=9

The equation has two equal roots which means discriminant is zero.

i.e. $b^2-4ac=0$

$(-3k)^2-4(k)(9)=0$

$9k^2-36k=0$

$9k(k-4)=0$

Either 9k=0 or k-4=0

i.e. k=0,k=4.

Reject k=0.

The value of k is 4.

#Learn more

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