Question

kx²-10x+3=0 x=1/3 find the value of k
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Answer 1

Answer:

hope fully it is helpful for you

Answer 2

X^2-X-12=0. (1)

KX^2+10X+3=0. (2)

MAY HAVE COMMON ROOT BY EQUATION (1)

X^2-X-12=0

X^2-(4-3)X-12=0

X(X-4)+3(X-4)=0

X+3=0, X-4=0

X= -3 ,X=4

PUTTING THE VALUE OF X IN EQUATION (2)

KX^2+10X+3=0

K(-3)^2+10(-3)+3=0

9K-30+3=0

9K=27

K=27/9

K=3,

X=4

KX^2+10X+3=0

K(4)^2+10(4)+3=0

16K+40+3=0

16K+43=0

16K= -43

K= -43/16