Math, asked by basavesh57, 11 months ago

kx2-20x+25=0 quadratic equation solve for kif it has real and equal roots​

Answers

Answered by agilandhanasekaran
18

Answer:

             k = 4

Step-by-step explanation:

kx² - 20x +25 = 0

Condition for real and equal roots​ : D = 0

D = b²-4ac

b²-4ac = 0

a = k, b = 20, c = 25

By substituting the values,

(20)²-4(k)(25) = 0

400 - 100k = 0

100k = 400

k = 400 / 100

k = 4

Answered by sprark
1

Answer:

the above written answer is correct

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