kx2-20x+25=0 quadratic equation solve for kif it has real and equal roots
Answers
Answered by
18
Answer:
k = 4
Step-by-step explanation:
kx² - 20x +25 = 0
Condition for real and equal roots : D = 0
D = b²-4ac
b²-4ac = 0
a = k, b = 20, c = 25
By substituting the values,
(20)²-4(k)(25) = 0
400 - 100k = 0
100k = 400
k = 400 / 100
k = 4
Answered by
1
Answer:
the above written answer is correct
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