Question

kx²+6x+1=0 Find the price of k if the roots of the class equation are equal​

Answer 1

Answer:

Value of k=9

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

kx² +6x + 1=0

kx² + 6x=0-1

kx²+6x =-1

kx²= -1-6x

k= (-1-6x)÷x²

k= -1/x² - 6x/x²

k= -1/x²- 6/x