Question

kya koi genius iska answer de ga ​

Answer 1

Step-by-step explanation:

Given that.

AC is the diameter of the circle with the centre C.

BD is the angle bisector of ∠ABC

So,

∠ABD=∠CBD (By property)

To Prove:-

Seg OD⊥ Seg AC

Proof:-

∠ABC=90

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(Angle inscribed in semicircle)

⇒∠ABD+∠CBD=90

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⇒∠ABD+∠ABD=90

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⇒∠2ABD=45

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⇒∠ABD=40

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Also,

∠AOD=2×∠ABD (Central Angletheorem)

⇒∠AOD=2×45

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