Kya please koi mujhe tan 15degree k value batayega.....????
Answers
Answered by
3
tan15°
tan(45°-30°)
(tan45-tan30°)/(1+tan45°tan30°)
(1-1/√3)/1+1/√3
after solving this u get....tan15° value..
Hope it helps uh...(:
tan(45°-30°)
(tan45-tan30°)/(1+tan45°tan30°)
(1-1/√3)/1+1/√3
after solving this u get....tan15° value..
Hope it helps uh...(:
Answered by
10
Hello friend!!!....Here is ur answer
tan15°= tan(45°-30°)
As we know that tan (A-B)= (tanA-tanB)/1+tanAtanB
Then,
tan (45-30)= (tan45-tan30)/1+tan45tan30
=> tan (45-30)= (1-1/root3)/1+1/root3
=> tan (45-30)= (root3-1)/(root3+1)
Hope it will help you
tan15°= tan(45°-30°)
As we know that tan (A-B)= (tanA-tanB)/1+tanAtanB
Then,
tan (45-30)= (tan45-tan30)/1+tan45tan30
=> tan (45-30)= (1-1/root3)/1+1/root3
=> tan (45-30)= (root3-1)/(root3+1)
Hope it will help you
yuvanshisehgal1:
hi
Similar questions
History,
7 months ago
Math,
1 year ago
Math,
1 year ago
Business Studies,
1 year ago
English,
1 year ago