Question

L,
14. The ten's digit of a two digit number is three times
the unit digit. The sum of the number and the unit
digit is 32. Find the number.
please give answer​

Answer 1

Answer:

number at unit place=8

three times the 8=24 +8=32

Answer 2

Answer

The required number is 31

$\large\bf\underline{Given}$

• The ten's digit of a two digit number is 3 times the unit digit
• The sum of the number and the unit digit is 32

$\bf\large\underline{To \ Find}$

• The number

$\bf\large\underline{Solution}$

Let the digits be x and y respectively

Therefore, the number is

$\sf\longrightarrow 10x + y$

$\sf\underline{\underline{\dag \: \: According \: to \: question : }}$

$\sf\implies x = 3y \dashrightarrow(1)$

$\sf \underline{ \underline{ \dag \: \: Again \: by \: question : }}$

$\sf\implies 10x + y + y = 32 \\\\ \sf\implies 10\times 3y + y + y = 32 \: \: \: \{ \because x = 3y\: from\: (1) \} \\\\ \sf\implies 32y = 32 \\\\ \sf\implies y = 1$

$\sf \underline{ \underline{Now \: putting \: the \: value \: of \: y \: in \: (1)}}$

$\sf\implies x = 3\times1 \\\\ \sf\implies x = 3$

Therefore, the required number is :

$\sf\longrightarrow 10\times3+1 \\\\ \sf\longrightarrow 30+1 \\\\ \sf\longrightarrow 31$