Question

[L-3M1T0] is the dimensional formula for

Answer 1

Answer:

Density.

Explanation:

We have,

$\\\tt [L^{-3} M^{1} T^{0} ]$

Where M corresponds to Mass L corresponds to length and T corresponds to time.

Therefore the given dimensions are to be translates as,

$\\\tt \dfrac{Mass}{(Length)^{3} } \\\\\tt = \dfrac{Mass}{Volume } \\\\\tt = Density$