Question

L (5,-8) , M (-7,-3) : Find distance between each the pairs of. point​

Answer 1

Answer:

$\huge{\boxed{\rm{\red{Distance=13 units}}}}$

Step-by-step explanation:

Given:-

L (5,-8) , M (-7,-3)

To find:-

Find distance between the points

Using formula:-

If(x1,y1) and (x2,y2) are two points then the distance between them is √{(x2-x1)²+(y2-y1)²} units

Solution:-

Given points are L (5,-8) , M (-7,-3)Let (x1,y1)=(5,-8)=>x1=5;y1=-8

(x2,y2)=(-7,-3)=>x2=-7;y2=-3

Now distance between the points L and M

=>LM=√{(-7-5)²+(-3-(-8))²}

=>LM=√{(-12)²+(-3+8)²}

=>LM=√{(-12)²+(5)²}

=>LM=√(144+25)

=>LM=√169

=>LM=√(13)²

=>LM=13 units

Answer:-

The distance between two points =13 units

Answer 2

Step-by-step explanation:

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Given :

Two Points L(5,-8) ,M(-7,-3)

To Find :

Distance between two given points

___________________________________________

We use distance formula to find out distance between any two points

$\bold{\boxed{\boxed{\pink{D= \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }}}}}$

X1=5;X2=-7;Y1=-8 & Y2=-3

$D= \sqrt{ {( - 7 - 5)}^{2} + {( - 3 + 8)}^{2} }$

$= \sqrt{ {(12)}^{2} + {(5)}^{2} }$

$= \sqrt{144 + 25} = \sqrt{169} ={\bold{\red{ 13}}}$

Hence ,the distance between L(5,-8) & M(-7,-3) is $\bold{\red{13\: units }}$

<-----------------13 units ----------------->

L(5,-8)•__________________•M(-7,-3)