Physics, asked by tiny000, 7 months ago

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54.The gravitational field strength at a point P on the Earth's surface is
numerically equal to
A. the acceleration of free fall at p
B. the change in potential energy per unit distance from p
C. the force acting on any body placed at p
D., the work done in bringing unit mass from Infinity to p​

Answers

Answered by maanvis2008
1

Answer:

Note that the field is numerically equal to the acceleration due to gravity at the location of the mass. On Earth's surface, the strength of the gravitational field is 9.8N/kg. It is independent of the size of the mass.

Explanation:

Answered by adventureisland
0

Answer :

C) The force acting on any body placed at P

Explanation :

  • The gravitational field strength at a point P on the Earth's surface is  numerically equal to  the force acting on any body placed at p. Because, The Earth's gravitational field strength is 10 N/kg (10 newtons per kilogram). This means that because a force of 10 N would attract an object weighing 1 kg towards the Earth's Centre. We perceive such forces as weight.
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