L A chord of a circle is equal to the radius of the
Circle. Find the angle subtended by the chord at
apoint on the minor arc and also at a point on the
major arc.
n.
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AB is equal to the radius of the circle.
In △OAB,
OA=OB=AB= radius of the circle.
Thus, △OAB is an equilateral triangle.
and ∠AOC=60°.
∠ACB=30°
Since, ACBD is a cyclic quadrilateral,
∠ACB+∠ADB=180° ....[Opposite angles of cyclic quadrilateral are supplementary]
⇒∠ADB=180°−30°=150°.
Thus, angle subtend by the chord at a point on the minor arc and also at a point on the major arc are 150° and 30°, respectively.
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