l am a number , tell my identity , take me 7 times over , and add a fifty, to reach a triple century , you still need forty
Answers
Answered by
1
hlooo dear...!!!
Let the number be x.
(7x + 50) + 40 = 300
7x + 90 = 300
7x = 300 − 90 (Transposing 90 to R.H.S.)
7x = 210
Dividing both sides by 7,
x = 30
Therefore, the number is 30.
Let the number be x.
(7x + 50) + 40 = 300
7x + 90 = 300
7x = 300 − 90 (Transposing 90 to R.H.S.)
7x = 210
Dividing both sides by 7,
x = 30
Therefore, the number is 30.
Answered by
1
Heya user !!!
Here's the answer you are looking for
Let the number be a
The question says take me 7 times over , and add a fifty, to reach a triple century , you still need forty
So, 7a + 50 + 40 = 300
7a + 90 = 300
7a = 300 - 90 = 210
a = 210/7 = 30
Therefore, the number is 30.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let the number be a
The question says take me 7 times over , and add a fifty, to reach a triple century , you still need forty
So, 7a + 50 + 40 = 300
7a + 90 = 300
7a = 300 - 90 = 210
a = 210/7 = 30
Therefore, the number is 30.
★★ HOPE THAT HELPS ☺️ ★★
Similar questions